M can do a piece of work in 40 days. He works at it for 5 days and then N alone finishes the remaining work in 42 days. The two together could complete the work in how many days?

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Satt Academy · Accepted Answer

M can do in 5 days =

540= 18 Part of the workRemaining work = (1 - 18) = (8-18) = 78 PartNow, N does 78 Part of the work in = 42 days ∴1 or complete part of the work done by N in = (42×87)=48 daysNow, (M+N)'s 1 day's work = (140+148)= (8840×48)=11240 partThey together do 11240 part of the work in =1 day's ∴They I or complete part of the work in = 24011 = 21 911 days

M can do a piece of work in 40 days. He works at it for 5 days and then N alone finishes the remaining work in 42 days. The two together could complete the work in how many days?

Question:
M can do a piece of work in 40 days. He works at it for 5 days and then N alone finishes the remaining work in 42 days. The two together could complete the work in how many days?

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M can do a piece of work in 40 days. He works at it for 5 days and then N alone finishes the remaining work in 42 days. The two together could complete the work in how many days?

Question: M can do a piece of work in 40 days. He works at it for 5 days and then N alone finishes the remaining work in 42 days. The two together could complete the work in how many days?

গণিত

Related Question

1 . দুইটি সংখ্যার গ. সা. গু ২১ এবং ল. সা. গু ৪৬৪১। একটি সংখ্যা ২০০ ও ৩০০ এর মধ্যবর্তী; | অপরটি কত?

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Satt AI

Hi, আমি SATT AI!

Question:
M can do a piece of work in 40 days. He works at it for 5 days and then N alone finishes the remaining work in 42 days. The two together could complete the work in how many days?